((1/9)^1-3x^2)=3^4x

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Solution for ((1/9)^1-3x^2)=3^4x equation: 


x in (-oo:+oo)

(1/9)^1-(3*x^2) = 3^4*x // - 3^4*x

(1/9)^1-(3*x^2)-(3^4*x) = 0

1/9-3*x^2-(3^4*x) = 0

1/9-3*x^2-81*x = 0

DELTA = (-81)^2-(-3*1/9*4)

DELTA = 19687/3

DELTA > 0

x = ((19687/3)^(1/2)+81)/(-3*2) or x = (81-(19687/3)^(1/2))/(-3*2)

x = ((19687/3)^(1/2)+81)/(-6) or x = (81-(19687/3)^(1/2))/(-6)

x in { ((19687/3)^(1/2)+81)/(-6), (81-(19687/3)^(1/2))/(-6) }

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